How to compare 2 logs with different bases

Question

0

2829

2

+386

My question is pretty much in the title.

Let's say we have

log base n (x) = log base a (b)

X=?

Thanks a lot!

TonyDrummer2 Aug 1, 2016

+23251

+10

Best Answer

Since log_n(x) = y can be written as n^y = x or x = n^y,

log_n(x) = log_a(b) can be written as n^log_a(b) = x or x = n^log_a(b)

geno3141 Aug 2, 2016

geno3141 · Answer 1 · 2016-08-02T12:06:17

Since log_n(x) = y can be written as n^y = x or x = n^y,

log_n(x) = log_a(b) can be written as n^log_a(b) = x or x = n^log_a(b)

Guest · Answer 2 · 2016-08-02T12:14:00

log base n (x) = log base a (b)

X=?

X=n^(log (b) / log(a))

Example: Log(base 2) of X =Log(base 5) of 100

X=2^(log(100)/log(5)) =7.266965.......etc.