The Q is
(logbased3 of x)^2 - 3logbased3 of x = 10
Solve for x. How should I deal with this parenthesis x? Should i use the U substitution? Thanks in advanced.
First, let y = log3(x). Then:
y2 - 3y - 10 = 0
This factors as: (y - 5)(y + 2) = 0
So y = 5 and y = -2 are solutions for y.
So, we have 5 = log3(x), which means x = 35
Also -2 = log3(x), which means x = 3-2