The Q is

(logbased3 of x)^2 - 3logbased3 of x = 10

Solve for x. How should I deal with this parenthesis x? Should i use the U substitution? Thanks in advanced.

First, let y = log_{3}(x). Then:

y^{2} - 3y - 10 = 0

This factors as: (y - 5)(y + 2) = 0

So y = 5 and y = -2 are solutions for y.

So, we have 5 = log_{3}(x), which means x = 3^{5}

Also -2 = log_{3}(x), which means x = 3^{-2}

THANKS! That cleara it up! Just basic algebraic manipulation.