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# How to differentiate 3/x^2 + 5x^2

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As stated in title

Guest Oct 25, 2017
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My interpretation: $${d\over dx}({3\over x^2}+5x^2)$$

By sum rule: $${d\over dx}{3\over x^2}+{d\over dx}5x^2$$

By definition of negative exponents: $${d\over dx}3x^{-2}+{d\over dx}5x^2$$

By constant product rule: $$3({d\over dx}x^{-2})+5({d\over dx}x^2)$$

By power rule: $$3(-2x^{-3})+5(2x)$$

Simplify to get $$10x-{6\over x^3}$$, which is your final answer.

Mathhemathh  Oct 25, 2017