+3693 Pythagorean theorem: $$a^2+b^2=c^2$$
a = leg#1
b = leg#2
c = hyptenuse
If "a" is equal to 3, and "b" is equal to 4, you would do this:
$$(3)^2+(4)^2 = c^2$$
Simplify the left side of the equation:
$$9+16 = c^2$$
Add the two numbers:
$$25=c^2$$
To find c (the hypotenuse), you would square both sides and then solve to get this"
$$5=c$$
Therefore, the hypotenuse is equal to 5 units.
This is just an example. However, you can use this formula for ANY number. I hope this helps! :)
$$\mathrm{\ }$$
+3693 Pythagorean theorem: $$a^2+b^2=c^2$$
a = leg#1
b = leg#2
c = hyptenuse
If "a" is equal to 3, and "b" is equal to 4, you would do this:
$$(3)^2+(4)^2 = c^2$$
Simplify the left side of the equation:
$$9+16 = c^2$$
Add the two numbers:
$$25=c^2$$
To find c (the hypotenuse), you would square both sides and then solve to get this"
$$5=c$$
Therefore, the hypotenuse is equal to 5 units.
This is just an example. However, you can use this formula for ANY number. I hope this helps! :)
$$\mathrm{\ }$$
