+35 Solve for y, \(\sqrt{50y}+2\sqrt{18y}=2\left(\sqrt{8y}+\sqrt{72y}\right)-5\)\(\)
I am trying to isolate the variable in one side and constant in other side, then I get
\(11\sqrt{2y}= 32y-5\),
after that I have no idea about how to solve the rest of the problem.
+1347 First, we can divide both sides by 11:
sqrt(2y) = 3y - 5/11
We can then square both sides of the equation to get rid of the radical:'
2y = 9y^2 - 35y + 25/121
This simplifies to 9y^2 - 44y + 25/121 = 0
Then we factor: (3y - 5/11)(3y - 5/22) = 0
So the solutions are y = 5/33 or y = 5/66.
But if we plug these in, we find that only y = 5/33 works.
+788
Solve for y. sqrt(50y) + (2)sqrt(18y) = 2(sqrt(8y) + sqrt(72y)) – 5
First, I'm going to take all the perfect squares out from under the radicals.
It looks like that's what you did, but I think there's a mistake in the addition.
(5)sqrt(2y) + (6)sqrt(2y) = (4)sqrt(2y) + (12)sqrt(2y) – 5
(11)sqrt(2y) = (16)sqrt(2y) – 5
(5)sqrt(2y) = 5
sqrt(2y) = 5 / 5 = 1
2y = 1
y = 1 / 2
check answer
sqrt(50y) + (2)sqrt(18y) = 2(sqrt(8y) + sqrt(72y)) – 5
sqrt(25) + (2)sqrt(9) = 2(sqrt(4) + sqrt(36)) –5
5 + 6 = 4 + 12 – 5
11 = 11
Looks pretty good.
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