Arithmetic Sequence: t(n) = m*n + b (Linear)
t(6) = 8
t(10) = 13
t difference = 4
output difference = 5
m = 1.25
6*1.25=7.5
8-7.5 = 0.5
t(n)=1.25n + 0.5
Sequences start at one. I am taking a shortcut on this by using a formula I know to quickly take the sum of any numbers in sequence:
0.5*4 = 2
(42 + 4)/2 * 1.25 = 12.5
12.5 + 2 = 14.5
Answer is g
Solve the following system: where F = First term, D=Common difference
{5 D + F = 8 | (equation 1)
9 D + F = 13 | (equation 2)
Subtract equation 1 from equation 2:
{F + 5 D = 8 | (equation 1)
0 F+4 D = 5 | (equation 2)
Divide equation 2 by 4:
{F + 5 D = 8 | (equation 1)
0 F+D = 5/4 | (equation 2)
Subtract 5 × (equation 2) from equation 1:
{F+0 D = 7/4 | (equation 1)
0 F+D = 5/4 | (equation 2)
F = 7/4 First term and D = 5/4 Common difference
The Sequence is: 7/4 + 12/4 + 17/4 + 22/4 =58/4 =14.50