How to do???

(2001^2001)/13 

 

\(y= {2001^{2001}\over13 }\\ 13y= 2001^{2001}\\ log(13y)= log( 2001^{2001})\\ log(13)+log(y)= 2001\;log( 2001)\\ log(y)= 2001\;log( 2001)-log(13)\\\)

 

log(y)=   2001\;log( 2001)-log(13)\\

 

2001*log( 2001)-log(13) = 6604.6814810087519746

 

\(log(y)=6604.6814810087519746\\ y=10^{6604.6814810087519746}\\ y=10^{0.6814810087519746}*10^{6604}\\\)

 

10^0.6814810087519746 = 4.8026507828589022669

 

\(y\approx 4.8026507828589022669 \times 10^{6604}\)