How to figure this out

2x + 3y = 0

x + 2y = -1

Notice that if we multiply the second equation by -2 all the way through, we get

-2x  - 4y = 2      

So we have

2x + 3y = 0

-2x  - 4y = 2        add these and we get

       -1y  = 2          divide both sides by -1

y  = -2      and using    x + 2y = -1     we have that  

x + 2(-2)  = -1 

x  -  4  = -1         add 4 to both sides

x = 3

So   (x , y)  = (3, -2)

To solve x or y?

Injusta, I believe he needs x.

Solve the following system: {2 x+3 y = 0 | (equation 1) x+2 y = -1 | (equation 2) Subtract 1/2 × (equation 1) from equation 2: {2 x+3 y = 0 | (equation 1) 0 x+y/2 = -1 | (equation 2) Multiply equation 2 by 2: {2 x+3 y = 0 | (equation 1) 0 x+y = -2 | (equation 2) Subtract 3 × (equation 2) from equation 1: {2 x+0 y = 6 | (equation 1) 0 x+y = -2 | (equation 2) Divide equation 1 by 2: {x+0 y = 3 | (equation 1) 0 x+y = -2 | (equation 2) Collect results: Answer: | | {x = 3              y = -2

alright, thank you all