+56 Hi, I have this problem where I need to solve for x in the end, but it's an exponent. Here's the problem and my work so far.
15278.4 = 27000(0.94)x _
----------- ----------------- = 0.56586 = 0.94x
27000 27000
So how do I get the x?
Thanks,
Lily
+561 You'll need to use logarithms. I'm going to assume they're a new concept for you.
They're a bit like the opposite of exponents.
Logarithms can rearrange an exponent as shown below.
\(b=a^x\)
\(log_ab=x\)
This would be log base a of b equals x
You may have seen a "log" button on a calculator (the one on this website in fact!), and that's what we use to solve these equations.
So for your question, it would be.
\(0.56586=0.94^x\)
\(log_{0.94}0.56586=x\)
So x is equal to 9.2025.
Calculators can be a little funny when trying to change the log base. If there is no option for the log base, it will be log base 10.
+561 You'll need to use logarithms. I'm going to assume they're a new concept for you.
They're a bit like the opposite of exponents.
Logarithms can rearrange an exponent as shown below.
\(b=a^x\)
\(log_ab=x\)
This would be log base a of b equals x
You may have seen a "log" button on a calculator (the one on this website in fact!), and that's what we use to solve these equations.
So for your question, it would be.
\(0.56586=0.94^x\)
\(log_{0.94}0.56586=x\)
So x is equal to 9.2025.
Calculators can be a little funny when trying to change the log base. If there is no option for the log base, it will be log base 10.
