how to find angle x of a triangle if the hypotenuse is 14 and the adjacient side is 10
+33653 cos x = adjacent/hypotenuse
cos x = 10/14
x = cos-1(10/14)
$${\mathtt{x}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{10}}}{{\mathtt{14}}}}\right)} \Rightarrow {\mathtt{x}} = {\mathtt{44.415\: \!308\: \!597\: \!193^{\circ}}}$$
+33653 cos x = adjacent/hypotenuse
cos x = 10/14
x = cos-1(10/14)
$${\mathtt{x}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{10}}}{{\mathtt{14}}}}\right)} \Rightarrow {\mathtt{x}} = {\mathtt{44.415\: \!308\: \!597\: \!193^{\circ}}}$$
