How to find solutions of a quadratic equation?

You start with a quadratic of the for  ax^2 + bx + c = 0

Then you can use the Quadratic Formula to solve for 'x

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

 

Or you can soemtimes factor the quadratic equation    

Example

x^2 + 5x + 6 = 0    can easily be factored to

(x+3)(x+2) = 0     which 'solves' for x = -3 or -2

 

 

Or ....you can graph it and find where y=o for the 'zeroes' tha satisfy the equation.....