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how do i find the the distance from the origin to the endpoint of the vertical axis.

 

 Oct 9, 2019

Best Answer 

 #5
avatar+19912 
+2

Looks like Chris is signed off presently.....

 

Looking for b ?

 

a^2 = b^2 + c^2

 

a = 58  (million miles)

c = 12  (million miles)

 

58^2 = b^2 + 12^2

b = 57   million miles

 Oct 9, 2019
 #1
avatar+105238 
+1

I'm assuming that the  distance from the center to the focus  =  46   =  c

 

116/2  =  a  = 58

 

In an ellipse

 

b^2 + c^2  = a^2        ....so

 

b^2  = a^2  - c^2

 

b^2  = 58^2  - 46^2

 

b^2  = 3136  - 2116

 

b = √[ 3136 - 2116 ]  = √1020 = 2√255

 

 

cool cool cool

 Oct 9, 2019
 #2
avatar
+1

oh no! the distance from the horizontal endpoint is 46 and for the other side its 70 miles add them together to get the full horizontal diamater 116. sorry for the confusion im not fully understanding the question to be honest. if it helps i could post the whole question. 

 Oct 9, 2019
 #3
avatar+105238 
+1

Go ahead and post it.....the distance from the horizontal endpoint to where  =  46   ???

 

 

 

cool cool cool

 Oct 9, 2019
 #4
avatar
0

Here is the orignal post 

 

https://web2.0calc.com/questions/calculus-help_15

 Oct 9, 2019
 #5
avatar+19912 
+2
Best Answer

Looks like Chris is signed off presently.....

 

Looking for b ?

 

a^2 = b^2 + c^2

 

a = 58  (million miles)

c = 12  (million miles)

 

58^2 = b^2 + 12^2

b = 57   million miles

ElectricPavlov Oct 9, 2019
 #6
avatar
+1

thank you!

 Oct 9, 2019

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