how do i find the the distance from the origin to the endpoint of the vertical axis.

Guest Oct 9, 2019

#5**+2 **

Looks like Chris is signed off presently.....

Looking for b ?

a^2 = b^2 + c^2

a = 58 (million miles)

c = 12 (million miles)

58^2 = b^2 + 12^2

b = 57 million miles

ElectricPavlov Oct 9, 2019

#1**+1 **

I'm assuming that the distance from the center to the focus = 46 = c

116/2 = a = 58

In an ellipse

b^2 + c^2 = a^2 ....so

b^2 = a^2 - c^2

b^2 = 58^2 - 46^2

b^2 = 3136 - 2116

b = √[ 3136 - 2116 ] = √1020 = 2√255

CPhill Oct 9, 2019

#2**+1 **

oh no! the distance from the horizontal endpoint is 46 and for the other side its 70 miles add them together to get the full horizontal diamater 116. sorry for the confusion im not fully understanding the question to be honest. if it helps i could post the whole question.

Guest Oct 9, 2019

#3**+1 **

Go ahead and post it.....the distance from the horizontal endpoint to where = 46 ???

CPhill Oct 9, 2019

#5**+2 **

Best Answer

Looks like Chris is signed off presently.....

Looking for b ?

a^2 = b^2 + c^2

a = 58 (million miles)

c = 12 (million miles)

58^2 = b^2 + 12^2

b = 57 million miles

ElectricPavlov Oct 9, 2019