Prove that ANY line going through the point (1,2) will ALWAYS intersect the curve/circle x^2+y^2=16 at TWO points. DONT USE ENGLISH USE EQUATIONS.
+9665 Radius of the circle 'x^2+y^2=16'
= \(\sqrt{16}\)
= 4
\(\because 1<4\text{ and }2<4\)
\(\therefore \text{Point (1,2) is in the circle, and any line going through it can't be the circle's tangent}\)
\(\therefore \text{Any line going through the point (1,2) will ALWAYS intersect the circle }x^2+y^2=16\\ \;\;\;\;\text{at 2 points.}\)
