How to quickly solve a to the nth power times a to the nth power minus 1 times a to the nth power minus 2, etc. for a = 2 and n= 3

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Guest Aug 26, 2015

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How to quickly solve a to the nth power times a to the nth power minus 1 times a to the nth power minus 2, etc. for a = 2 and n= 3

Is this what you mean ?

$\\a^n*a^{(n-1)}*a^{(n-2)} ...... *a^{n-n}\\\\ =2^3*2^{(3-1)}*2^{(3-2)} *2^{(3-3)}\\\\ =2^3*2^{2}*2^{1} *2^{0}\\\\ =8*4*2*1\\\\ =64$

Melody Aug 27, 2015

Melody · Answer 1 · 2015-08-27T11:20:06

How to quickly solve a to the nth power times a to the nth power minus 1 times a to the nth power minus 2, etc. for a = 2 and n= 3

Is this what you mean ?

$\\a^n*a^{(n-1)}*a^{(n-2)} ...... *a^{n-n}\\\\ =2^3*2^{(3-1)}*2^{(3-2)} *2^{(3-3)}\\\\ =2^3*2^{2}*2^{1} *2^{0}\\\\ =8*4*2*1\\\\ =64$