+0  
 
+11
1
2422
1
avatar
lim.(x->0+) e^(x^2)/cos(x^2)
 Jan 26, 2012
 #1
avatar+3146 
+1
Input: lim( e^(x^2)/cos(x^2), x=0 )

Result: 1
 Jan 26, 2012

4 Online Users

avatar
avatar