$${\sqrt[{{\mathtt{3}}}]{{\mathtt{32}}}}$$
23^(1/3)
It is an irrational number so this is an approximation.
$${{\mathtt{23}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right)} = {\mathtt{2.843\: \!866\: \!979\: \!851\: \!565\: \!4}}$$
