How to simplify 27*(1/3)^(n-1)

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Guest Dec 5, 2014

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Best Answer

$$\\27*(1/3)^{n-1}\\
=3^3* \;\;1/3^{n-1}\\
=3^3/3^{n-1}\\
=3^{3-(n-1)}\\
=3^{3-n+1}\\
=3^{4-n}\\$$

Melody Dec 5, 2014

Melody · Answer 1 · 2014-12-05T04:00:36

$$\\27*(1/3)^{n-1}\\
=3^3* \;\;1/3^{n-1}\\
=3^3/3^{n-1}\\
=3^{3-(n-1)}\\
=3^{3-n+1}\\
=3^{4-n}\\$$

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