how to simplify sen(2arcsen(4/5))?

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Guest Jan 26, 2015

+130536

+5

Best Answer

I think we have

sin (2 arcsin (4/5) )

Let arcsin (4/5) = Θ ... and this is an angle whose sin = 4/5 ... so the cosΘ = ±3/5

So we have

sin (2Θ) = 2sinΘcosΘ = 2(4/5)(±3/5) = ±24/25

CPhill Jan 26, 2015

CPhill · Answer 1 · 2015-01-26T05:30:05

I think we have

sin (2 arcsin (4/5) )

Let arcsin (4/5) = Θ ... and this is an angle whose sin = 4/5 ... so the cosΘ = ±3/5

So we have

sin (2Θ) = 2sinΘcosΘ = 2(4/5)(±3/5) = ±24/25