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how to solve 16 times 2 to the third power over 2 to the second power

 Mar 11, 2015

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$${\frac{\left({\mathtt{16}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{3}}}\right)}{\left({{\mathtt{2}}}^{{\mathtt{2}}}\right)}} = {\mathtt{32}}$$

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 Mar 11, 2015
 #1
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+5
Best Answer

$${\frac{\left({\mathtt{16}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{3}}}\right)}{\left({{\mathtt{2}}}^{{\mathtt{2}}}\right)}} = {\mathtt{32}}$$

Guest Mar 11, 2015

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