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how do you solve the equation ∫( 4/x-3/x-2/x-1/x+3x^2+1337)dx

 Dec 30, 2015

Best Answer 

 #1
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Take the integral:
integral (3 x^2-2/x+1337) dx
Integrate the sum term by term and factor out constants:
  =  3 integral x^2  dx-2 integral 1/x dx+1337 integral 1 dx
The integral of x^2 is x^3/3:
  =  x^3-2 integral 1/x dx+1337 integral 1 dx
The integral of 1/x is log(x):
  =  x^3-2 log(x)+1337 integral 1 dx
The integral of 1 is x:
Answer: | =  x^3+1337 x-2 log(x)+constant

 Dec 30, 2015
 #1
avatar
+10
Best Answer

Take the integral:
integral (3 x^2-2/x+1337) dx
Integrate the sum term by term and factor out constants:
  =  3 integral x^2  dx-2 integral 1/x dx+1337 integral 1 dx
The integral of x^2 is x^3/3:
  =  x^3-2 integral 1/x dx+1337 integral 1 dx
The integral of 1/x is log(x):
  =  x^3-2 log(x)+1337 integral 1 dx
The integral of 1 is x:
Answer: | =  x^3+1337 x-2 log(x)+constant

Guest Dec 30, 2015
 #3
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0

Answer=x^3+1337x+c

 Jan 11, 2016

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