How to solve loga14

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How to solve loga14 given loga2=3.01, loga6=.778 and loga7 is .845

Guest Aug 31, 2017

CPhill · Answer 1 · 2017-08-31T05:36:19

log_a14

Given log_a2=3.01, log_a6=.778 and log_a7 is .845

Note that we only need log_a 2 = 3.01 and log_a 7 = .845 to solve this

By a log property......log m + log n = log ( m * n) ....so.....

log_a 2 + log_a 7 = log_a ( 2 * 7 ) = log_a (14)

3.01 + .845 = log_a (14) = 3.855

BTW - "a" couldn't be a "real" base!!!