+0  
 
0
192
1
avatar

How to solve loga14 given loga2=3.01, loga6=.778 and loga7 is .845

Guest Aug 31, 2017
 #1
avatar+86859 
+1

 

loga14

Given  loga2=3.01, loga6=.778 and loga7 is .845

 

Note that we only need   loga 2 = 3.01   and loga 7  = .845     to solve this

 

By a log property......log m  + log n  =  log ( m * n)    ....so.....

 

loga 2  +   loga 7  =     loga  ( 2 * 7 )  =   loga (14)

 

3.01    +   .845   =    loga (14)   =   3.855

 

BTW -  "a"  couldn't be a "real" base!!!

 

 

cool cool cool

CPhill  Aug 31, 2017
edited by CPhill  Aug 31, 2017

10 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.