how to solve sin^-1(cos(2pi/3))?

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Guest Apr 9, 2015

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Best Answer

sin^-1(cos(2pi/3)

cos 2pi/3 = -1/2 ....so...

sin-1(-1/2) = -pi/6

CPhill Apr 9, 2015

CPhill · Answer 1 · 2015-04-09T03:26:07

sin^-1(cos(2pi/3)

cos 2pi/3 = -1/2 ....so...

sin-1(-1/2) = -pi/6

Melody · Answer 2 · 2015-04-09T12:27:54

Remember that the domain for inverse sine is $$-\pi/2\le \pi/2$$

So only 1st and 4th quadrant answers are relevant. :)