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how to solve sin^-1(cos(2pi/3))?

Guest Apr 9, 2015

Best Answer 

 #1
avatar+92674 
+10

sin^-1(cos(2pi/3)

cos 2pi/3  = -1/2   ....so...

sin-1(-1/2) = -pi/6

 

  

CPhill  Apr 9, 2015
 #1
avatar+92674 
+10
Best Answer

sin^-1(cos(2pi/3)

cos 2pi/3  = -1/2   ....so...

sin-1(-1/2) = -pi/6

 

  

CPhill  Apr 9, 2015
 #2
avatar+94105 
+5

Remember that the domain for inverse sine is     $$-\pi/2\le \pi/2$$

 

So only 1st and 4th quadrant answers are relevant.  :)

Melody  Apr 9, 2015

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