6^(x+8)=12
Solve for x over the real numbers: 6^(x+8) = 12
Take the logarithm base 6 of both sides: x+8 = (log(12))/(log(6))
Subtract 8 from both sides: Answer: | x = (log(12))/(log(6))-8
6^(x+8)=12 take the log of both sides
log 6^(x + 8) = log 12 and by a log property we can write
(x + 8) log 6 = log 12 divide both sides by log 6
(x + 8) = [ log 12 / log 6] subtract 8 from each side
x = [ log12 / log 6 ] - 8 = about -6.613
