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 Its in dutch but in english its solve x for the above equation

 Jan 9, 2015

Best Answer 

 #1
avatar+23245 
+5

2log(x - 3)  =  1 + log(x) + log(2) - log(5)

log(x - 3)² - log(x) - log(2) + log(5)  =  1    (multiplier goes inside as an exponent)

log[ 5(x - 3)² / (2x) ]  =  1                         (subtraction --->   division; addition   --->  multiplication)

5(x - 3)² / (2x) = 10                                  (raise both sides as exponents upon 10)

(x - 3)² / (2x)  =  2                                   (divide by 5)

(x - 3)²  = 4x                                           (multiply by 2x)

x² - 6x + 9  =  4x                                     (multiply out)

x² - 10x + 9  =  0

(x - 9)(x - 1)  =  0

x  =  9   <---- answer                 x = 1   <--- won't check

 Jan 9, 2015
 #1
avatar+23245 
+5
Best Answer

2log(x - 3)  =  1 + log(x) + log(2) - log(5)

log(x - 3)² - log(x) - log(2) + log(5)  =  1    (multiplier goes inside as an exponent)

log[ 5(x - 3)² / (2x) ]  =  1                         (subtraction --->   division; addition   --->  multiplication)

5(x - 3)² / (2x) = 10                                  (raise both sides as exponents upon 10)

(x - 3)² / (2x)  =  2                                   (divide by 5)

(x - 3)²  = 4x                                           (multiply by 2x)

x² - 6x + 9  =  4x                                     (multiply out)

x² - 10x + 9  =  0

(x - 9)(x - 1)  =  0

x  =  9   <---- answer                 x = 1   <--- won't check

geno3141 Jan 9, 2015

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