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sin^4 ( A ) + sin^2 ( A ) cos^2 ( A ) + cos^2 ( A ) = 1

 Aug 6, 2019
 #1
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how to solve this

\(\sin^4 ( A ) + \sin^2 ( A ) \cos^2 ( A ) + \cos^2 ( A ) = 1\)

 

\(\begin{array}{|rcll|} \hline \sin^4 ( A ) + \sin^2 ( A ) \cos^2 ( A ) + \cos^2 ( A ) &=& 1 \\ \sin^2 ( A )\sin^2 ( A )+ \sin^2 ( A ) \cos^2 ( A ) + \cos^2 ( A ) &=& 1 \\ \sin^2 ( A ) \left(\sin^2 ( A )+ \cos^2 ( A )\right) + \cos^2 ( A ) &=& 1 \\ \sin^2 ( A ) \left(\underbrace{\sin^2 ( A )+ \cos^2 ( A )}_{=1} \right) + \cos^2 ( A ) &=& 1 \\ \sin^2 ( A )*1 + \cos^2 ( A ) &=& 1 \\ \underbrace{\sin^2 ( A ) + \cos^2 ( A )}_{=1} &=& 1 \\ \hline \end{array} \)

 

laugh

 Aug 6, 2019

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