$${\frac{{\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{8}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{6}}}}\right)}}{{{\mathtt{16}}}^{\left({\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right)}}}$$
