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The parabola has the equation y = ax^2 + bx + c.

 

Find a+b+c.

 Feb 11, 2020
 #1
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+1

The  vertex  is  ( 2,1)

 

The x coordinate  of the  vertex is given by

 

-b/ [2a] = 2

 

-b= 4a

 

b = -4a

 

And another point on the parabola  is   (0, 5)    so  c  =  5

 

So   we can solve this

 

a (2)^2  + b (2)^2 + c  = 1

 

a(2)^2   - 4a (2)  + 5  =1

 

4a  -8a  + 5  =1

 

-4a  = -4

 

a = 1

 

And b = -4(1)  =- 4

 

So....the function is

 

x^2  - 4x  + 5

 

So

 

a + b +  c  =

 

1  - 4  +  5  =

 

2

 

 

 

cool cool cool

 Feb 11, 2020
 #2
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+1

Find a+b+c.

 

Hello Guest!

 

\(f(x) =y= (x-2)*(x-2)+1\\ y=x^2-4x+4+1\\ y=x^2-4x+5\\ \)

\(a=1\\ b=-4\\ c=5\\ a+b+c=2 \)

 

laugh  !      asinus

 Feb 11, 2020
edited by asinus  Feb 11, 2020

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