how to solve this task Log 32 2×+1/3-7× = 1/5
Similar to the first one you solved:
log32(( 2x+1)/(3-7x) = 1/5
32^(1/5) = (2x+1)/(3-7x)
2 = (2x+1)/(3-7x)
2(3-7x) = (2x+1)
6-14x=2x+1
5 = 16x
x=5/16
Similar to the first one you solved:
log32(( 2x+1)/(3-7x) = 1/5
32^(1/5) = (2x+1)/(3-7x)
2 = (2x+1)/(3-7x)
2(3-7x) = (2x+1)
6-14x=2x+1
5 = 16x
x=5/16
Dude you already sovled the tassk that is the right answer man good job i finally did math for once in my life!