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how to solve this task Log 32 2×+1/3-7× = 1/5

 Oct 23, 2016
edited by Guest  Oct 23, 2016

Best Answer 

 #3
avatar+25842 
+5

Similar to the first one you solved:

log32(( 2x+1)/(3-7x) = 1/5

 

32^(1/5) =  (2x+1)/(3-7x)

2 = (2x+1)/(3-7x)

 

2(3-7x) = (2x+1)

6-14x=2x+1

5 = 16x

x=5/16

 Oct 23, 2016
 #1
avatar+257 
0

IDK bro i dont know what you mean?!?!?!??!?!?!?

 Oct 23, 2016
 #2
avatar
+1

How to solve this task?

 Oct 23, 2016
 #3
avatar+25842 
+5
Best Answer

Similar to the first one you solved:

log32(( 2x+1)/(3-7x) = 1/5

 

32^(1/5) =  (2x+1)/(3-7x)

2 = (2x+1)/(3-7x)

 

2(3-7x) = (2x+1)

6-14x=2x+1

5 = 16x

x=5/16

ElectricPavlov Oct 23, 2016
 #4
avatar+257 
0

Dude you already sovled the tassk that is the right answer man good job i finally did math for once in my life!

 Oct 23, 2016

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