+0  
 
0
3040
6
avatar

how would I do this? A competitive high school swimmer takes 52 seconds to swim 100 yards. What is his rate in km/hr? (1 m = 1.0936 yards)

 Apr 30, 2015

Best Answer 

 #6
avatar
+5

thanks 

 Apr 30, 2015
 #1
avatar+870 
0

velocity=distance/time

You have to convert 100 yards into km, 52 s into hours, then use this formula.

 Apr 30, 2015
 #2
avatar
0

could you post an example equation please?

 Apr 30, 2015
 #3
avatar+870 
0

Example: It took me 3 hours to run 15 km: so my average velocity (v) is equal to: $$v=\frac {15}{3}=5$$

So my average velocity is equal to 5 km/h

 Apr 30, 2015
 #4
avatar+26393 
+5

how would I do this? A competitive high school swimmer takes 52 seconds to swim 100 yards. What is his rate in km/hr? (1 m = 1.0936 yards)

$$\small{\text{
$
\begin{array}{l}
\dfrac{100~\rm{yard}}{52~\rm{s} } \cdot
\dfrac{ 1~\rm{m} } { 1.0936~\rm{yard} } \cdot
\dfrac{ 1~\rm{km} } { 1000~\rm{m} } \cdot
\dfrac{ 60~\rm{s} } { 1~\rm{min} } \cdot
\dfrac{ 60~\rm{min} } { 1~\rm{h} } \\\\
=\dfrac{100\cdot 60\cdot 60}{52\cdot 1.0936\cdot 1000}\cdot \dfrac{ \rm{km}}{ \rm{h} } \\\\
=6.33053851781\cdot \dfrac{ \rm{km}}{ \rm{h} } \\\\
\approx 6.33 \cdot \dfrac{ \rm{km}}{ \rm{h} }
\end{array}
$}}$$

 Apr 30, 2015
 #5
avatar+870 
0

That's it !

 Apr 30, 2015
 #6
avatar
+5
Best Answer

thanks 

Guest Apr 30, 2015

1 Online Users

avatar