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\({36x^3 - 64x}\)

 

i know that this is a difference of squares... but i'm not sure how can i get the textbook answer of \({4x(3x +4)(3x -4)}\)? i got \({x(6x - 8)(6x + 8)}\) isn't that the same thing? and please show step by step! 

Guest Jul 9, 2018
edited by Guest  Jul 9, 2018
edited by Guest  Jul 9, 2018
edited by Guest  Jul 9, 2018
 #1
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Factor the following:
36 x^3 - 64 x

Factor common terms out of 36 x^3 - 64 x.
Factor 4 x out of 36 x^3 - 64 x:
4 x (9 x^2 - 16)

Express 9 x^2 - 16 as a difference of squares.
9 x^2 - 16 = (3 x)^2 - 4^2:
4 x (3 x)^2 - 4^2
Factor the difference of two squares. (3 x)^2 - 4^2 = (3 x - 4) (3 x + 4):
4 x (3 x - 4) (3 x + 4)

Guest Jul 9, 2018
 #2
avatar+93654 
+1

YES yours is the same thing BUT yours is not fully factored.

You can factor 2 out of each of the brackets and then you will get the text book answer.

 

Yours is not wrong, it is just not finished.   wink

 

This is a good question becasue you are obviously trying to understand.

Why don't you join up and become a part of our community. 

 

It is free and you won't get sent any annoying advertising sent to you.

You can ask for an email to be sent if someone answers your questions.

AND you get a watchlst that I am sure all members make good use of. 

Plus you can message people directly if you want, that can be quite handy :)

Melody  Jul 17, 2018
edited by Melody  Jul 17, 2018

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