how would I show work for >> f(x)= -2/3 * x2 - x +5, f(6)

f(x)= -2/3 * x2 - x  +5, f(6)

This just means that we want to put 6 into the function and evaluate....so we have

(-2/3)(6)^2  - 6 + 5   =   -24 - 6 + 5   =  -30 + 5  = -25