+130511 how would we do 42 - 12 ÷ 6 × 2 + 7 in order of operations
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We first perform any multiplications / divisions as we encounter them from left to right....so we have
42 - (12 / 6) X 2 + 7 =
42 - (2 x 2) + 7 =
42 - 4 + 7 =
38 + 7 =
45
Notice that this would have been better written as:
42 - [ (12/6) X 2] + 7 Here, it's clear that we should work inside the brackets first !!
+130511 how would we do 42 - 12 ÷ 6 × 2 + 7 in order of operations
---------------------------------------------------------------------------------------------------------------------------
We first perform any multiplications / divisions as we encounter them from left to right....so we have
42 - (12 / 6) X 2 + 7 =
42 - (2 x 2) + 7 =
42 - 4 + 7 =
38 + 7 =
45
Notice that this would have been better written as:
42 - [ (12/6) X 2] + 7 Here, it's clear that we should work inside the brackets first !!
