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How would you approximate this hypergeometric distribution

 

H (x / 40000; 39001; 20000)

 

19001<=x<=20000

 

as a binominal / normal distribution?

 Jun 9, 2016
 #1
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hypergeometric distribution | number of trials | n (positive integer) number of successes | m (positive integer) population size | N (positive integer)

 

mean | (m n)/N
standard deviation | sqrt((m n (N-m) (N-n))/(N-1))/N
variance | (m n (1-m/N) (N-n))/((N-1) N)
skewness | (sqrt(N-1) (N-2 m) (N-2 n))/((N-2) sqrt(m n (N-m) (N-n)))
kurtosis | ((N-1) N^2 ((3 m (N-m) (n^2 (-N)+(n-2) N^2+6 n (N-n)))/N^2-6 n (N-n)+N (N+1)))/(m n (N-3) (N-2) (N-m) (N-n))

 Jun 9, 2016

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