how would you do the problem 11 2/5 /11 4/5 ? i have to simplify it and my math book is not helping

Simplify the following:
(11+2/5)/(11+4/5)

Put 11+4/5 over the common denominator 5. 11+4/5  =  (5×11)/5+4/5:
(11+2/5)/((5×11)/5+4/5)

5×11  =  55:
(11+2/5)/(55/5+4/5)

55/5+4/5  =  (55+4)/5:
(11+2/5)/((55+4)/5)

55+4 = 59:
(11+2/5)/(59/5)

Put 11+2/5 over the common denominator 5. 11+2/5  =  (5×11)/5+2/5:
((5×11)/5+2/5)/(59/5)

5×11  =  55:
(55/5+2/5)/(59/5)

55/5+2/5  =  (55+2)/5:
((55+2)/5)/(59/5)

55+2 = 57:
(57/5)/(59/5)

Multiply the numerator by the reciprocal of the denominator, (57/5)/(59/5) = 57/5×5/59:
(57×5)/(5×59)

(57×5)/(5×59) = 5/5×57/59 = 57/59:
Answer: | 57/59

11^2/5 /  11^4/5   =     multiply top/bottom by  11^1/5 =

[11^2/5 * 11^1/5]  / 11  =

11^3/5  / 11   =

(11³)^1/5  / 11  =

(1331)^1/5 / 11 

Simplify the following:
(11^(2/5))/(11^(4/5))

Rationalize the denominator. (11^(2/5))/(11^(4/5))  =  (11^(2/5))/(11^(4/5))×(11^(1/5))/(11^(1/5))  =  (11^(2/5) 11^(1/5))/(11):
(11^(2/5) 11^(1/5))/(11)

Combine powers. (11^(2/5) 11^(1/5))/(11) = 11^(2/5+1/5-1):
11^2/5+1/5-1

Put 2/5+1/5-1 over the common denominator 5. 2/5+1/5-1  =  2/5+1/5-(5)/5:
11^2/5+1/5-(5)/5

2/5+1/5-(5)/5  =  (2+1-5)/5:
11^(2+1-5)/5

2+1-5 = -2:
11^(-2/5)

Rationalize the denominator. 1/11^(2/5)  =  1/11^(2/5)×(11^(3/5))/(11^(3/5))  =  (11^(3/5))/(11):
Answer: | (11^(3/5))/(11)