How would you find the value of r in this equation: 1/sin(49) = sin(20)/sin(r)

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Guest Nov 6, 2014

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Best Answer

1/sin(49) = sin(20)/sin(r) cross multiplying, we have

sin(r) = sin(49)*sin(20)

sin(r) = 0.2581258787973758 and using the sine inverse, we have

sin^-1(0.2581258787973758) = r = about 14.96°

CPhill Nov 6, 2014

CPhill · Answer 1 · 2014-11-06T07:30:30

1/sin(49) = sin(20)/sin(r) cross multiplying, we have

sin(r) = sin(49)*sin(20)

sin(r) = 0.2581258787973758 and using the sine inverse, we have

sin^-1(0.2581258787973758) = r = about 14.96°