How would you solve this for h?$${\mathtt{A}} = \left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\mathtt{ah}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\mathtt{bh}}$$
I would start by factoring such that...
$${\mathtt{A}} = {\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{h}}{\mathtt{\,\times\,}}\left({\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}\right)$$
From there you can rearrange to find that....
$${\frac{{\mathtt{2}}{A}}{\left({\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}\right)}} = {\mathtt{h}}$$
I would start by factoring such that...
$${\mathtt{A}} = {\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{h}}{\mathtt{\,\times\,}}\left({\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}\right)$$
From there you can rearrange to find that....
$${\frac{{\mathtt{2}}{A}}{\left({\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}\right)}} = {\mathtt{h}}$$
