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A right triangle has a base of 3x-5 and a height of 2x-4. Its perimeter is x2+5x+11. What is the length of the hypotenuse? 

Guest Jan 2, 2018
 #1
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3x -  5          2x  -  4       x^2 + 5x + 11

 

Note that.... if we subtract  the base and height from the perimeter, what remains is the hypotenuse

 

So....adding the base and height we get 7x  - 9

 

And subtracting this from the perimeter, we have

 

[ x^2  + 5x + 11]  -  [  7x  -  9 ]   =

 

x^2 - 2x  +  20   =  the hypotenuse

 

 

cool cool cool

CPhill  Jan 2, 2018
 #2
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Thank you :)

Guest Jan 2, 2018

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