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A circle centered at $(0,-8)$ passes through the point $(2,-5).$ Find the equation of the circle. Write your equation in the form "$(x - h)^2 + (y - k)^2 = r^2$".

 Feb 4, 2020

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 #1
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A circle centered at $(0,-8)$ passes through the point $(2,-5).$ Find the equation of the circle. Write your equation in the form "$(x - h)^2 + (y - k)^2 = r^2$".

laugh

 Feb 4, 2020
 #1
avatar+12528 
+3
Best Answer

A circle centered at $(0,-8)$ passes through the point $(2,-5).$ Find the equation of the circle. Write your equation in the form "$(x - h)^2 + (y - k)^2 = r^2$".

laugh

Omi67 Feb 4, 2020

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