What is the probability that a point chosen at random in the given figure will be inside the larger triangle and outside the smaller triangle?
Enter your answer, as a fraction in simplest form, in the box.
P(inside larger triangle and outside smaller triangle) =
The area of the larger triangle is (1/2) (base) * (height ) = (1/2)(10) * (6) = 30 cm^2
The area of the smaller triangle is : (1/2) (base ) ( height) = (1/2) (4)(4) = 8 cm^2
So...the area beween these triangles = 30 - 8 = 22 cm^2
P( inside larger triangle and outside smaller triangle) =
area between triangles / area of larger triangle =
22 / 30 = 11 / 15