If h(x) = (−x + 1)2 − 5 and g(x) = −x − 2 , then (h ◦ g)(x) =?
h(x) = (−x + 1)2 − 5 = -2x+2-5 = -2x-3
(h ◦ g)(x) = -2[−x − 2] - 3
(h ◦ g)(x) = [2x + 4] - 3
(h ◦ g)(x) = 2x + 1
