HW PROB WARNING (again...)

This time, I want to CHECK my answer with you smart people.

PROBLEM:

Consider the parabola \(y=-5x^2+17x-12\) . What is the vertex of this parabola?
Enter your answer as a coordinate pair, that is, as \((x,y)\) where \(x\) and \(y\) are replaced by numbers.

\(My\ Work:\)

\(Axis\ of\ symetry\ (x\ value) \\=\frac{-b}{2a} \\=\frac{-17}{-10} \\=\frac{17}{10} \\=1.7\)
 

\(Plugging\ it\ in\ (y\ value) \\-5(1.7)^2+17(1.7)-12 \\-5(2.89)+17(1.7)-12 \\-14.45+28.9-12 \\-14.45+16.9 \\+2.45\)

\(Answer: \\(1.7,2.45)\)

Therefore, I think that the answer is (1.7,2.45)

-\(tommarvoloriddle \)

EDIT:
If I did somehow get it right, post an emoji (or something) please in the answer section...
If I got it wrong ( probably ) just say I got it wrong, why, and how I should do it next time.