+0  
 
0
2217
1
avatar

Hya, my question says Hays is standing outside on a sunny day. He is 6ft tall and casts a 4ft shadow. What is the distance from the top of Hays' head to the end of  his shadow?

Round to the nearest tenth, if necessary. Thanks so much btw :) This is the only question out of 24 that I need help with

 Jan 20, 2017
 #1
avatar+129839 
0

Distance   =  √[6^2 + 4^2]  = √[36 + 16]  = √52 =  2√13 ≈ 7.2 ft

 

 

cool cool cool

 Jan 20, 2017

1 Online Users