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avatar+445 

\(hyperbola H = x^2-y^2=1 \)

When stretched in the x direction by \(1/3\)

it becomes \(9x^2-y=1 \)

please explain i am really confused by this as I thought in this situation you should substitute x to 3x 

YEEEEEET  Oct 13, 2018
edited by YEEEEEET  Oct 13, 2018

Best Answer 

 #1
avatar+94098 
+3

I would not call it streched as it is being shrunk but anyway.

 

\((3x)^2-y^2=1\\ is\\ 9x^2-y^2=1\)

 

 

So x is replaced  by 3x just as you wanted to do :)

Melody  Oct 13, 2018
 #1
avatar+94098 
+3
Best Answer

I would not call it streched as it is being shrunk but anyway.

 

\((3x)^2-y^2=1\\ is\\ 9x^2-y^2=1\)

 

 

So x is replaced  by 3x just as you wanted to do :)

Melody  Oct 13, 2018
 #2
avatar+445 
+1

Thank you!

YEEEEEET  Oct 13, 2018

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