\(hyperbola H = x^2-y^2=1 \)
When stretched in the x direction by \(1/3\)
it becomes \(9x^2-y=1 \)
please explain i am really confused by this as I thought in this situation you should substitute x to 3x
I would not call it streched as it is being shrunk but anyway.
\((3x)^2-y^2=1\\ is\\ 9x^2-y^2=1\)
So x is replaced by 3x just as you wanted to do :)