Hyperbola conic section

Question

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$hyperbola H = x^2-y^2=1$

When stretched in the x direction by $1/3$

it becomes $9x^2-y=1$

please explain i am really confused by this as I thought in this situation you should substitute x to 3x

YEEEEEET Oct 13, 2018

edited by YEEEEEET Oct 13, 2018

+118696

+3

Best Answer

I would not call it streched as it is being shrunk but anyway.

$(3x)^2-y^2=1\\ is\\ 9x^2-y^2=1$

So x is replaced by 3x just as you wanted to do :)

Melody Oct 13, 2018

Melody · Answer 1 · 2018-10-13T11:41:44

I would not call it streched as it is being shrunk but anyway.

$(3x)^2-y^2=1\\ is\\ 9x^2-y^2=1$

So x is replaced by 3x just as you wanted to do :)

YEEEEEET · Answer 2 · 2018-10-13T02:20:04

Thank you!