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avatar+148 

For a certain hyperbola \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1,\)
where \(a>b \) the angle between the asymptotes is \(60^\circ.\). Find \(\frac{a}{b}.\)

 Oct 19, 2019
 #1
avatar+109383 
+1

See the image below :

 

 

 

The equation of the hyperbola  is

 

x^2         y^2

____  -  _____   =     1

   3           1

 

 

a = √3       

b  =  1

 

So

 

a / b    =  √3  / 1

 

 

 

cool cool cool

 Oct 19, 2019
 #2
avatar+148 
-1

Thank You so much. This helps a lot!!

 Oct 19, 2019

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