Hey.
I'm looking at a cat curve ( 143.3-15.25 cosh(0.0438x)=0)
any body got any ideas on how to solve for the x intercepts?
Any help would be great! Thanks in advance
+130477 143.3-15.25 cosh(0.0438x)=0
Subtract 143.3 from both sides
-15.25cosh(0.0438x) = - 143.3
Divide both sides by -15.25
cosh(0.0438x) = 143.3/15.25
Take the arccosh to isolate x
arccosh(143.3/15.25) = 0.0438x
Divide both sides by 0.0438
arccosh(143.3/15.25)/0.0438 = x = about 66.9102
As I'm not overly familiar with these functions, WolframAlpha also gives the negative of this as the other [real solution] x intercept......here's a pic :
just re-arrange to get
cosh(0.438X) = 143.3/15.25
then
(0.438X) = arc cosh( 143.3/15.25),and just do the arithmetic.
The cosh function is never zero,by the way,as it is e^x + e^(-x).The x axis is an asymptote of the function.
+26397
this is not a arcus function "arc cosh" is wrong, this is a area - function area cosh(x) or arcosh(x) is right!
see: https://en.wikipedia.org/wiki/Inverse_hyperbolic_function
