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# I almost solved this question, but I'm stuck at the last part, can someone explain this?

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Kumar bought 5 posters and 11 cards with 1/3 of his money. The cost of each poster was 3 times the cost of each card. He bought some more posters with 3/4 of his remaining money.

(a) What was the greatest number of cards Kumar could buy with 1/3 of his money?

(b) How many posters did Kumar buy in all?

Sep 10, 2021

#1
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Kumar bought 5 posters and 11 cards with 1/3 of his money. The cost of each poster was 3 times the cost of each card. He bought some more posters with 3/4 of his remaining money.

(a) What was the greatest number of cards Kumar could buy with 1/3 of his money?

(b) How many posters did Kumar buy in all?

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1 card = x          1 poster = 3x

5(3x) + 11x = 26x

a)    With 1/3 of his money, Kumar could've bought 26 cards.

b)    He bought 18 posters

Sep 11, 2021
#2
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I will solve this question in elementary way

(a)     the cost of each poster was 3

times the cost of each card, so the money

for 1 poster can buy 3 card

5 * 3 = 15

15 + 11 = 26

So he can buy 26 cards

(b)   3/4 of his remaining money = 3/4 * (1 - 1/3)

is 1/2 of his all money       = 3/4 * 2/3

= 1/2

1/2 / 1/3 * 26 = 3/2 * 26 = 39

39 / 3 = 13

13 + 5 = 18

So he bought 18 posters

Sep 12, 2021