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(127)^4−x     =    9^2x−1

 

 

 

Note that 4-x after 127 is all exponents, and 2x-1 after 9 is all exponents.

 Feb 19, 2020
 #1
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thanks for the note:) 

(127)^4−x     =    9^2x−1

should be written as

127^(4−x)     =    9^(2x−1)

 

Looking for real solutions.

\(127^{4−x}     =    9^{2x−1}\\ log(127^{4−x} )    =    log(9^{2x−1})\\ (4-x)log(127 )    =    (2x-1)log(9)\\ 4log127+log9 = 2xlog9+xlog127\\ 4log127+log9 = x(2log9+log127)\\ x=\frac{4log127+log9}{2log9+log127} \\ \)

x is approximately 2.335

 Feb 19, 2020

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