(127)^4−x = 9^2x−1
Note that 4-x after 127 is all exponents, and 2x-1 after 9 is all exponents.
+118609 thanks for the note:)
(127)^4−x = 9^2x−1
should be written as
127^(4−x) = 9^(2x−1)
Looking for real solutions.
\(127^{4−x} = 9^{2x−1}\\ log(127^{4−x} ) = log(9^{2x−1})\\ (4-x)log(127 ) = (2x-1)log(9)\\ 4log127+log9 = 2xlog9+xlog127\\ 4log127+log9 = x(2log9+log127)\\ x=\frac{4log127+log9}{2log9+log127} \\ \)
x is approximately 2.335
