+262 need to make factorization but something went wrong
that's what i did:
4a^2(2a+3)-6a(2a+3)+7(2a+3)=
now what do i need to do?
+118608 (I have been asked for more explanation)
Say if have
3x+5x-18x these are all like terms so I can add them (3+5-18)x = -10x
They are like terms because they are all a number followed by the same letter
5x= 5*x = (2+3)x that would be true too.
6(x+7)-2(x+7) = 6 lots of (x+7) - 2 lots of (x+7) = (6-2) lots of (x-7) = 4(x-7)
3(2y+7)+5(2y+7)+x(2y+7)
each time exactly the same thing is in the bracket so you have
3 lots of the bracket +5 lots of the bracket + x lots of the bracket.
this is (3+5+x) lots of the bracket = (8+x)(2y+7)
You will probably need to think about it for a bit 
+118608 Hi Sabi92
Lets look at what you did
$$\\4a^2\textcolor[rgb]{0,0,1}{(2a+3)}-6a\textcolor[rgb]{0,0,1}{(2a+3)}+7\textcolor[rgb]{0,0,1}{(2a+3)}\\\\
=(4a^2-6a+7)\textcolor[rgb]{0,0,1}{(2a+3)}$$
Yes that is perfect
+118608 (I have been asked for more explanation)
Say if have
3x+5x-18x these are all like terms so I can add them (3+5-18)x = -10x
They are like terms because they are all a number followed by the same letter
5x= 5*x = (2+3)x that would be true too.
6(x+7)-2(x+7) = 6 lots of (x+7) - 2 lots of (x+7) = (6-2) lots of (x-7) = 4(x-7)
3(2y+7)+5(2y+7)+x(2y+7)
each time exactly the same thing is in the bracket so you have
3 lots of the bracket +5 lots of the bracket + x lots of the bracket.
this is (3+5+x) lots of the bracket = (8+x)(2y+7)
You will probably need to think about it for a bit
