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Altitudes $\overline{AD}$ and 

$\overline{BE}$

 of 

$\triangle ABC$

 intersect at 

$H$

. If 

$\angle BAC = 54^\circ$

 and 

$\angle ABC = 52^\circ$

, then what is

$\angle AHB$

 ?

 Dec 31, 2020
 #1
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0

I got that angle AHB = 66 degrees.

 Dec 31, 2020
 #2
avatar+846 
0

Angle AHB = 106º  smiley

jugoslav  Dec 31, 2020

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