I am having trouble with this question... could someone lend me a hand

Altitudes $\overline{AD}$ and 

$\overline{BE}$

 of 

$\triangle ABC$

 intersect at 

$H$

. If 

$\angle BAC = 54^\circ$

 and 

$\angle ABC = 52^\circ$

, then what is

$\angle AHB$

 ?