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I am in algebra 1. Can you help me simplify the cube root of 128 over 54

 May 20, 2015

Best Answer 

 #1
avatar+130466 
+5

3√[128 / 54] =

 

3√[(64*2) / (27*2)] =

 

3√[64 / 27] =

 

3√64 / 3√27  =

 

4 / 3

 

 

 May 20, 2015
 #1
avatar+130466 
+5
Best Answer

3√[128 / 54] =

 

3√[(64*2) / (27*2)] =

 

3√[64 / 27] =

 

3√64 / 3√27  =

 

4 / 3

 

 

CPhill May 20, 2015

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